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5=(1/625)^x-5
We move all terms to the left:
5-((1/625)^x-5)=0
Domain of the equation: 625)^x-5)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+1/625)^x-5)+5=0
We multiply all the terms by the denominator
-((+1+5*625)^x-5)=0
We calculate terms in parentheses: -((+1+5*625)^x-5), so:We get rid of parentheses
(+1+5*625)^x-5
We add all the numbers together, and all the variables
3126^x-5
Back to the equation:
-(3126^x-5)
-3126^x+5=0
We move all terms containing x to the left, all other terms to the right
-3126^x=-5
x=-5/1
x=-5
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